Induced current in a circular loop

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A circular conducting loop with a radius of 1/π cm has one half made of 1Ω resistance and the other half of 5Ω resistance. When a changing magnetic field induces a 5V emf in the loop, the current can be calculated as 5/(1+5) = 5/6 A. The challenge arises in determining the voltage reading across two diametrically opposite junction points due to the differing resistances. The voltmeter reading varies based on its placement within the magnetic field, demonstrating that the voltage is not constant across the loop. The discussion emphasizes the importance of understanding how geometry and resistance distribution affect induced current and voltage measurements.
  • #31
DrZoidberg said:
If there is no solid core you can move the voltmeter above the coil and get a voltage that's somewhere in between +4.17 and -0.83 or -4.17 and + 0.83 depending on which way around you connected the meter. At some point it will read 0 but that point is probably not exactly above the coil because the setup is not symmetric since the two resistances are different.
Well I have studied the circuit using surface charge feedback mechanism too..My calculations for voltmeter reading match for both the cases (left and right side) with those done using your suggested method..:smile::smile: Exactly above the coil, the voltmeter will read 1.67 V, not 0 ,as you correctly predicted using the symmetry argument:smile:..Thanks again for your help..
 
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