Induced current in copper wire

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Homework Help Overview

The problem involves a square loop made of copper wire and examines the induced current due to a changing magnetic field. The loop's dimensions and the properties of copper are provided, along with the rate of change of the magnetic field.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants discuss the application of Faraday's law and the need to differentiate between the area of the loop and the cross-sectional area of the wire. Questions arise about the setup of the problem, particularly regarding the calculation of magnetic field changes.

Discussion Status

Some participants have provided clarifications regarding the areas involved and the use of Faraday's law. There is acknowledgment of the complexity of the problem, and participants are exploring different approaches to setting it up correctly.

Contextual Notes

Participants note the distinction between the loop's area and the wire's radius, indicating potential confusion in interpreting the problem's requirements. The discussion reflects an ongoing exploration of the problem's components without reaching a consensus on the solution.

vigintitres
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Homework Statement


A square loop, 5.3 m on a side, is made of copper wire, 0.9 mm in radius. A 3.2 T magnetic field, perpindicular to the loop is increasing at the rate of 0.29 T/s. The resistivity of copper is 1.7 x 10^-8 ohm*m. Find the induced current. Answer in units of A.


Homework Equations


I'm assuming I need to use Faraday's law where I = V/R = magnetic flux/resistivity * time


The Attempt at a Solution


What actually threw me was the fact that the loop has a radius. So the area can't just be 5.3 squared and I don't think I need to calculate the area of a cylinder? Well I tried finding the initial value for the magnetic field then subtracting that from the final value after 1 second since it increases .29 T/s. I was just getting large answers and I can tell they would be somewhat large due to the large value of B, but I'm honestly stuck on how to set this beast up correctly.
 
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Hi vigintitres,

vigintitres said:

Homework Statement


A square loop, 5.3 m on a side, is made of copper wire, 0.9 mm in radius. A 3.2 T magnetic field, perpindicular to the loop is increasing at the rate of 0.29 T/s. The resistivity of copper is 1.7 x 10^-8 ohm*m. Find the induced current. Answer in units of A.


Homework Equations


I'm assuming I need to use Faraday's law where I = V/R = magnetic flux/resistivity * time


The Attempt at a Solution


What actually threw me was the fact that the loop has a radius. So the area can't just be 5.3 squared and I don't think I need to calculate the area of a cylinder? Well I tried finding the initial value for the magnetic field then subtracting that from the final value after 1 second since it increases .29 T/s. I was just getting large answers and I can tell they would be somewhat large due to the large value of B, but I'm honestly stuck on how to set this beast up correctly.

The loop doesn't have a radius; the wire has a radius. This problem has several parts, and one part will require the area of the loop, and another part will use the cross sectional area of the wire.

So to answer your question. the area of the loop is just the area of a square. Does that help?
 
yes, thanks that will get me started at least. Am I correct that I am going to use Faraday's law and was the method of finding the initial B and the final B and subtracting the difference ok for this problem?
 
vigintitres said:
yes, thanks that will get me started at least. Am I correct that I am going to use Faraday's law and was the method of finding the initial B and the final B and subtracting the difference ok for this problem?

That should work for that part of Farday's law; or you could leave it as a derivative.
 

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