Induced Current in Square Loop

[qlzlahs]

Homework Statement

A 21cm×21cm square loop has a resistance of 0.12 Ω . A magnetic field perpendicular to the loop is B=4t−2t^2, where B is in tesla and t is in seconds.
(A) What is the current in the loop at t=0.0s?
(B) What is the current in the loop at t=1.0s?

Homework Equations

for a square loop, B = (√2)(μ_0*I)/(π*R), where R is the length of the side

The Attempt at a Solution

(A) I assumed that at t = 0, B = 4(0) - 2(0^2) = 0.
0 = (√2)(μ_0*I)/(π*.21), but that means I = 0 A and that didn't work.
Help please? Thanks.

 

[cnh1995]

You must use Faraday's law of electromagnetic induction.

 

[qlzlahs]

You must use Faraday's law of electromagnetic induction.

So I use V = -A*(dB/dt), then use V = IR to find the current?

 

[cnh1995]

So I use V = -A*(dB/dt), then use V = IR to find the current?

Correct..