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Induced Current in Square Loop

  1. Dec 17, 2015 #1
    1. The problem statement, all variables and given/known data
    A 21cm×21cm square loop has a resistance of 0.12 Ω . A magnetic field perpendicular to the loop is B=4t−2t^2, where B is in tesla and t is in seconds.
    (A) What is the current in the loop at t=0.0s?
    (B) What is the current in the loop at t=1.0s?

    2. Relevant equations
    for a square loop, B = (√2)(μ_0*I)/(π*R), where R is the length of the side

    3. The attempt at a solution
    (A) I assumed that at t = 0, B = 4(0) - 2(0^2) = 0.
    0 = (√2)(μ_0*I)/(π*.21), but that means I = 0 A and that didn't work.
    Help please? Thanks.
     
  2. jcsd
  3. Dec 17, 2015 #2

    cnh1995

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    You must use Faraday's law of electromagnetic induction.
     
  4. Dec 17, 2015 #3
    So I use V = -A*(dB/dt), then use V = IR to find the current?
     
  5. Dec 17, 2015 #4

    cnh1995

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    Correct..
     
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