Induced Electric Field: Near Magnetic Field?

[dev70]

Can electric field be induced at a point near a time varying uniform magnetic field? "Near" means not the in the place where magnetic field exist. But at a point outside the field's presence.

 

[mfb]

You can induce electric fields everywhere. Why do you expect that it would not be possible somewhere?

 

[Meir Achuz]

Can electric field be induced at a point near a time varying uniform magnetic field? "Near" means not the in the place where magnetic field exist. But at a point outside the field's presence.

You probably meant 'by a magnetic field, but not in the place where the magnetic field exists.

A time varying magnetic field will have time varying vector potential
\frac{\partial{\bf A}}{\partial t} that can exist beyond the field, and induce an E field. This is like the 'Aharonov-Bohm' effect.

 

[elfmotat]

Yes. Say, for example, there's a long solenoid with a time-varying current I(t) running through it. The resulting magnetic field is nonzero only inside the solenoid. However, (assuming ∂B/∂t isn't zero) the electric field induced will also be nonzero outside of the solenoid.

 

[mfb]

A time varying magnetic field will have time varying vector potential
\frac{\partial{\bf A}}{\partial t} that can exist beyond the field, and induce an E field.

Only in areas where there is a changing magnetic field.

However, (assuming ∂B/∂t isn't zero) the electric field induced will also be nonzero outside of the solenoid.

∂B/∂t ≠ 0 implies that there is a magnetic field (apart from some specific points in time maybe).

 

[andrien]

Take a circular area beyond the region of changing magnetic field,but it should include changing magnetic field area then
E.2∏R=-∏r².∂B/∂t,E is induced in region beyond WHERE B changes.

 

[Meir Achuz]

Only in areas where there is a changing magnetic field.

B= curl A. Apply Stokes' theorem for a B field in a solenoid.
This gives an A outside the solenoid, where there is no B.

 

[mfb]

I don't see how your quote and your post are related. You can get a non-zero A everywhere if you like - even in a perfect vacuum, as you have gauge freedom. But you do not get an electric field without a changing magnetic field or some charge distribution.

 

[elfmotat]

∂B/∂t ≠ 0 implies that there is a magnetic field (apart from some specific points in time maybe).

Yes, but only inside the solenoid. The electric field it produces also "exists" (is nonzero) outside the solenoid where B=0.

 

[mfb]

The electric field it produces also "exists" (is nonzero) outside the solenoid where B=0.

Sorry, but what you want just violates the laws of physics.

$$curl(B)=\frac{1}{c}\frac{\partial E}{\partial t} + \frac{4\pi}{c} j$$
You do not want currents and no magnetic field? => electric field is time-invariant. You cannot switch it on or off.

This means that a time-independent charge distribution (which might consist of moving charges) is the only relevant option for a source of an electric field.

 

[elfmotat]

Sorry, but what you want just violates the laws of physics.

$$curl(B)=\frac{1}{c}\frac{\partial E}{\partial t} + \frac{4\pi}{c} j$$
You do not want currents and no magnetic field? => electric field is time-invariant. You cannot switch it on or off.

This means that a time-independent charge distribution (which might consist of moving charges) is the only relevant option for a source of an electric field.

No, it certainly doesn't. If there's a long solenoid of radius a and turn density n with a current I(t) running through it, it will induce a magnetic field B(t)=μ₀nI(t) inside the solenoid. Outside of the solenoid B=0 everywhere.

Evaluating the integral ∫E∙ds=-∂/∂t ∫B∙dA ⇔ E=-μ₀na² I'(t) / 2r

Even though B=0 outside the solenoid, it still produces a nonzero E outside the solenoid.

 

[K^2]

Sorry, but what you want just violates the laws of physics.

Transformers violate laws of physics? You learn something new every day!

Sorry, I shouldn't be mean about it. It is a bit counter-intuitive. But yeah, if you take an infinitely-long solenoid, the magnetic field is ONLY present inside the solenoid. Yet you can wrap another solenoid around it, and induce a current on it by time-varying the current on the inner-solenoid. The B-field outside remains zero, but E-field is non-zero.

This all has to do with curl of the electric field being governed by ∂B/∂t. Outside of the solenoid, both curl and divergence of E is zero, but it doesn't mean that the field itself is zero. Feel free to verify that circular E field with 1/R intensity satisfies conditions of both curl and divergence being zero. (In other words for E = E_0\frac{\hat{\phi}}{r}, \nabla \cdot E = 0 and \nabla \times E = 0 everywhere except r=0.)

 

[andrien]

I have shown in post no.6 that even outside a solenoid if one take a circular area and if it encloses the region of changing magnetic field then electric field will be induced at far distances also.

 

[mfb]

Ah ok, you are right. So we need a coil of infinite length, where B(t) changes linear in time. This gives a constant (in time), circular E(t) and no magnetic field outside.

 

[dev70]

then..how will a time varying electric field induce magnetic field and where?