A 5.97 m long steel beam is accidentally dropped by a construction crane from a height of 6.82 m. The horizontal component of the Earth's magnetic field over the region is 12.2 [tex]\mu T[/tex]. The acceleration of gravity is 9.8 m/s^2. What is the induced emf in the beam just before impact with the Earth, assuming its long dimension remains in a horizontal plane, oriented perpendicularly to the horizontal component of the Earth's magnetic field? Answer in units of mV. I know that E= change in flux/change in time To get the change in time I used the equation x(t)= x_o +v_o*t +.5 gt^2 where x_o=v_o=0 and x(t)= 6.82 m. solving for t gave me .834 s. Then for the flux I think it's just B*L= 72.8... but I don't think thats right... Can someone please help me?