Induced EMF Problem 6.6 Solution Help

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Homework Help Overview

The discussion revolves around Problem 6.6 related to induced electromotive force (EMF) and magnetic flux changes. Participants are examining the direction of induced current in response to a changing magnetic flux, specifically focusing on part (b) of the problem.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to understand the reasoning behind the direction of the induced current, questioning whether a decreasing magnetic flux should lead to a clockwise or counterclockwise current. Other participants affirm the solution's correctness and clarify that the induced current must oppose the change in flux, suggesting a counterclockwise direction.

Discussion Status

Participants are actively engaging with the problem, with some providing guidance on the reasoning behind the induced current's direction. There is a recognition of differing interpretations regarding the behavior of the magnetic flux and its implications for the induced current.

Contextual Notes

There is an ongoing exploration of the relationship between the magnetic flux direction and the induced current, with specific reference to the sine and cosine functions in the context of time. The original poster expresses confusion about the implications of the flux being "less negative" and its effect on the induced current direction.

izelkay
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Homework Statement


It's Problem 6.6 on this page:
http://web.ece.ucdavis.edu/~lxgliu/eec130a/2012winter/hw9s.pdf

It has the solution and everything. I don't understand part (b) though.

Homework Equations

The Attempt at a Solution


[/B]
For part (b), I thought the direction of the induced current flow would flow as to oppose the change in the magnetic flux. The change in the magnetic flux here is dΦ/dt = -6.9sin(2πx10^4t) (V).

They chose t = 0, but on an interval t =0 to say t = π/2, the sine function in the magnetic flux is greater than 0, which means dΦ/dt is negative and less than 0 right? Which in turn means the flux is decreasing. However, the flux is going INTO the page (-x direction) so shouldn't a decreasing flux mean it's getting less negative? So then the induced current I think should flow CLOCKWISE to oppose this change. This isn't what the solution says though, and I can't understand the way they did it. Can someone explain the fault in my reasoning?
 
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The solution is correct. the flux initially into the page is decreasing so the induced current will be in a direction so as to oppose this change i.e. to increase the flux. by producing a field coming out of the page, counter clockwise. Your derivative is negative but it is deceasing into the page so the induced current mus be increasing the flux out of the page.
 
gleem said:
The solution is correct. the flux initially into the page is decreasing so the induced current will be in a direction so as to oppose this change i.e. to increase the flux. by producing a field coming out of the page, counter clockwise. Your derivative is negative but it is deceasing into the page so the induced current mus be increasing the flux out of the page.
Okay so like they said the initial flux is in the -x direction into the page and is maximum at t = 0. It varies as a cosine initially, so it is decreasing. Here's where my confusion is:

in the -x direction,
cos(0) = -1, maximum
cos(pi/4) = -1/√2

Is it not getting more positive (i.e, closer to 0) and starting to try to point in the +x-direction?
 
bump
 
The induced current (CCW) is producing a field out of the page.
 

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