Induced EMF Problem 6.6 Solution Help

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SUMMARY

The discussion focuses on Problem 6.6 from a physics homework assignment regarding induced electromotive force (EMF) and the direction of induced current. The key conclusion is that the induced current flows counterclockwise to oppose the decreasing magnetic flux, which is directed into the page. The confusion arises from interpreting the change in magnetic flux; while the derivative of flux is negative, it indicates a decrease in the negative flux, necessitating a current that increases the flux out of the page. The solution provided is confirmed to be correct.

PREREQUISITES
  • Understanding of Faraday's Law of Electromagnetic Induction
  • Knowledge of magnetic flux and its directionality
  • Familiarity with sine and cosine functions in relation to time-varying fields
  • Basic principles of induced current direction based on Lenz's Law
NEXT STEPS
  • Study Faraday's Law and its applications in electromagnetic systems
  • Explore Lenz's Law for a deeper understanding of induced current direction
  • Investigate the relationship between magnetic flux and induced EMF in AC circuits
  • Practice solving problems involving time-varying magnetic fields and induced currents
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Students studying electromagnetism, physics educators, and anyone seeking to understand the principles of induced EMF and current direction in electromagnetic systems.

izelkay
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Homework Statement


It's Problem 6.6 on this page:
http://web.ece.ucdavis.edu/~lxgliu/eec130a/2012winter/hw9s.pdf

It has the solution and everything. I don't understand part (b) though.

Homework Equations

The Attempt at a Solution


[/B]
For part (b), I thought the direction of the induced current flow would flow as to oppose the change in the magnetic flux. The change in the magnetic flux here is dΦ/dt = -6.9sin(2πx10^4t) (V).

They chose t = 0, but on an interval t =0 to say t = π/2, the sine function in the magnetic flux is greater than 0, which means dΦ/dt is negative and less than 0 right? Which in turn means the flux is decreasing. However, the flux is going INTO the page (-x direction) so shouldn't a decreasing flux mean it's getting less negative? So then the induced current I think should flow CLOCKWISE to oppose this change. This isn't what the solution says though, and I can't understand the way they did it. Can someone explain the fault in my reasoning?
 
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The solution is correct. the flux initially into the page is decreasing so the induced current will be in a direction so as to oppose this change i.e. to increase the flux. by producing a field coming out of the page, counter clockwise. Your derivative is negative but it is deceasing into the page so the induced current mus be increasing the flux out of the page.
 
gleem said:
The solution is correct. the flux initially into the page is decreasing so the induced current will be in a direction so as to oppose this change i.e. to increase the flux. by producing a field coming out of the page, counter clockwise. Your derivative is negative but it is deceasing into the page so the induced current mus be increasing the flux out of the page.
Okay so like they said the initial flux is in the -x direction into the page and is maximum at t = 0. It varies as a cosine initially, so it is decreasing. Here's where my confusion is:

in the -x direction,
cos(0) = -1, maximum
cos(pi/4) = -1/√2

Is it not getting more positive (i.e, closer to 0) and starting to try to point in the +x-direction?
 
bump
 
The induced current (CCW) is producing a field out of the page.
 

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