Current vs. Induced Current: What's the Difference?

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In a circuit with an open switch, no current flows, resulting in no magnetic flux or induced current. Induced current arises specifically from changes in the magnetic field, opposing the change that creates it, as described by Faraday's law. Even without a primary current source, an induced current can occur in a secondary circuit due to magnetic field changes. The distinction between current and induced current lies in their causes, with induced current linked to dynamic magnetic flux rather than static electric fields. Understanding these concepts is crucial for grasping electromagnetic principles in physics.
Soaring Crane
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If a switch of a circuit system of a wire loop is open, then no current flows. There would also be no magnetic flux and induced current if it remains open, right?

What is the difference between current and induced current? I know the latter arises from a change in the magnetic field, but what else is there to know?


Thanks.
 
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Soaring Crane said:
What is the difference between current and induced current? I know the latter arises from a change in the magnetic field, but what else is there to know?


Thanks.

An induced current has a direction such that the magnetic field due to the induced current opposes the change in the magnetic field that induces the current

marlon
 
Besides, if there is no current in the primary chain (coming from a battery) there will still be an induced current in the secondary chain (no battery connected to it) because the magnetic field will 'break down' and thus it will induce a current in the second chain. the two chains are mostly interconnected by some ferromagnetic material

marlon
 
The difference of both names & concepts stands in the cause that produces the curerents."The latter" appears from a change in the magnetic flux (which is a scalar,BTW,so we worry only with changes in time,and not in space)...I believe that's what the theorem/law of Faraday says...:wink:

So to use equations,the difference could be visualized from

\vec{E}=-\nabla\phi

and

\mbox{induced \ electromotive \ tension} =-\frac{d}{dt}\iint_{S} \vec{B}\cdot \vec{n} \ dS

Daniel.
 
Perhaps the most striking difference is the fact that electric potential has meaning only for E-fields that are produced by static charges (like the E-field between two electrodes); it has NO meaning for E-fields that are produced by induction...

to dextercioby : talking about blabla-tension and multi-dimensional integrals ain't going to do much good in the grade K-12-level, amigo

marlon
 
marlon said:
to dextercioby : talking about blabla-tension and multi-dimensional integrals ain't going to do much good in the grade K-12-level, amigo

marlon

1.I didn't realize the thread was in K-12.
2.In HS,everyone knows what an electromotive tension is...

Daniel.
 
Thread 'Correct statement about size of wire to produce larger extension'
The answer is (B) but I don't really understand why. Based on formula of Young Modulus: $$x=\frac{FL}{AE}$$ The second wire made of the same material so it means they have same Young Modulus. Larger extension means larger value of ##x## so to get larger value of ##x## we can increase ##F## and ##L## and decrease ##A## I am not sure whether there is change in ##F## for first and second wire so I will just assume ##F## does not change. It leaves (B) and (C) as possible options so why is (C)...

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