Undergrad Induced metric in general case

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The Gauss formula for the induced metric is expressed as g_{\mu \nu} = G_{ab} \frac{\partial X^a \partial X^b}{\partial x^\mu \partial x^\nu}, where G represents the metric of the embedding space. The discussion centers on whether this formula remains valid when the embedding space lacks a Minkowski-like metric and is intrinsically curved. The consensus is that the formula does indeed hold true in such cases. This confirms that the induced metric can be applied regardless of the curvature of the embedding space. Understanding this relationship is crucial for applications in differential geometry and general relativity.
gerald V
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Does the familiar Gauss formula for the embedded metric hold if the embedding space itself is intrinsically curved?
The Gauss formula for the induced metric reads ##g_{\mu \nu} = G_{ab}\frac{\partial X^a \partial X^b}{\partial x^\mu \partial x^\nu}##, where ##G## is the metric of the embedding space, the capital ##X## are positions in the embedding space, the little ##x## are positions inside the embedded manifold and the ##\partial## denote partial differentiation (no notion of covariance present).


I have read some literature on embedding, pullbacks and so on, but they are all quite abstract. My only question is whether the above formula equally holds if the embedding space is not equipped with a Minkowski-like metric (in some number of dimensions), in particular if the embedding space itself is intrinsically curved.

From what I know the answer is yes but I would be grateful for confirmation or correction.


Thank you very much in advance.
 
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