Induction motor windings, number of turns per phase and per pole

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SUMMARY

The discussion focuses on calculating the number of turns per phase in induction motor windings using the formula Nph = Eph / (4.44 * f * FL * K). Key variables include RMS phase voltage (Eph), frequency (f), involved flux (FL), number of pole pairs (p), and winding factor (K). The conversation highlights the importance of understanding the flux distribution for different pole configurations, particularly in machines with multiple poles per phase. The participants seek clarification on the relationship between pole count and winding design to maintain consistent flux loading.

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Electrical engineers, motor design specialists, and students studying induction motor theory will benefit from this discussion, particularly those interested in optimizing winding configurations for performance and efficiency.

rulmismo
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Hi,
I have some question regarding windings on induction motors, if anybody can help.
Reviewing some literature (*), the usual formulae to get the number of turns per phase of a induction motor winding is
  • Eph= RMS phase voltage [V]
  • Nph= number of turns of phase winding
  • f= frequency [Hz]
  • FL="involved" flux (typically set by a limit of Bmean * involved area, being Bmean about 0.7T for a typical machine) [Wb]
  • p=number of pole pairs
  • K= winding factor
Nph= Eph / (4.44 * f * FL * K )

My question is regarding the flux to be used. Most of the books and references I found talk in this equation of a "per pole" flux, but voltage in the formulae is phase voltage (and you can have several poles per phase winding), so my current understanding is:
- if p=1 (2 pole machine), Nph shall be concentrated in one winding, and flux involved is the "mean" of the whole machine
- if p=2,(4 pole machine), flux loading (Bmean) must be the same so I think:
if poles are feed in paralel (is this the usual case?), Npole=Nphase of the p=1 machine, to keep same flux loading.
if poles are feed in series, Npole=Nphase/p, to keep same flux loading (so same total turns, but distributed between the poles.)
- p=3....

I would appreciate any insight or correction, any reference to a worked example of higher pole machine design or windings could also help.

Thanks!

(*) References just in case can help anybody
ref1
ref2
ref3
 
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Does the 4 pole motor uses single phase power? I am not sure why you would have a 4 pole motor if you have 3 phase power. If it is a single phase motor, the pole windings will have to have different reactance in order to create a phase difference between the two pole pairs. So the windings will depend on how that phase difference is achieved.

AM
 
These are m-phase motor, in the usual case m is three, then phase windings are the same, but displaced 120º. My question is related to how many turns you would use per pole, so to keep flux within saturation limits.

A n-pole motor (with n>2) is used when you want a lower synchronous speed.
 

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