Inelastic Collision from different but not opposite directions. HELP

[A PP4L K]

Homework Statement

Two skaters collide and embrace, in a completely inelastic collision. Alfred, whose mass is 83 kg is originally moving east with a speed of 6.3km/hr. The other skater (m=55 kg) is originally moving north with a speed of 7.8km/hr. What is the velocity (magnitude and direction) after the collision?

Homework Equations

1)M1V1 + M2V2 = (M1 + M2)V’
2)F∙Δt = M∙Vf - M∙Vi
3)P = MV
4)Ft = Δp
5)I = MVF - MVi

The Attempt at a Solution

M1= 83kg
V1= 1.75 m/s
M2= 55kg
V2= 2.17 m/s


Honestly I have no idea where to even start. I know how to do regular inelastic, and elastic, collision problems. This is an extra credit problem that I am trying to do, so if anyone could show me how to work one of these out or could hint me in the right direction it would be very much appreciated! :)

 

[ben.tien]

Okay. So you start off with the equation M1V1 + M2V2 = (M1+M2)V'. Treat momentum as a vector and solve for it in components.

 

[popo902]

keep in mind that the velocities of each skater are on different axes
like ben.tien said, use that equation M1V1 + M2V2 = (M1 +M2)V and add the velocities as vectors in components. That should get you on the right path