Inelastic collisions in 2 dimensions

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SUMMARY

The discussion centers on calculating the final velocity of a target after an inelastic collision with an arrow. The target has a mass of 0.800 kg and an initial velocity of 3.0 m/s west, while the arrow has a mass of 20.0 g and an initial velocity of 260 m/s north. The key equation used is the conservation of momentum, expressed as m1v1i + m2v2i = m1v1f + m2v2f. The distinction between inelastic and completely inelastic collisions is emphasized, with the conclusion that insufficient information is provided to determine the final velocity without assuming a completely inelastic scenario.

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SohailS
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I am unsure how to proceed with this problem because it is asking for the final velocity of one of the two objects given the initial velocities. This is an inelastic collision not a completely inelastic collision, which means the two objects do not stick together. The book makes a distinction between the two.

If you can give me some hints as how to proceed it would be truly helpful.

Homework Statement



A 0.800 kg target slides along the ice at 3.0 m/s [W], when it is hit by a 20.0 g arrow
moving at 260 m/s [N], as part of a show. Find the final velocity of the target after the
inelastic collision.

Given:

let east and north be positive

m1 = 0.800 kg
v1 = 3.0 m/s [W]
m2 = 0.0200 kg
v2 = 260 m/s [N]

find v1f

Homework Equations



Pti=Ptf

m1v1i + m2v2i = m1v1f + m2v2f

The Attempt at a Solution



The question is asking for the final velocity of the target which is find v1f
This is an inelastic collision, not a completely inelastic collision, this means the arrow will not stick to the target.

vix = -3.0 m/s
viy = 260 m/s

a2dh0g.png


Pxi=(0.8)(-3)=-2.4 Ns
Pyi=(0.02)(260)=5.2 Ns
 
Last edited:
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Hello.

If the arrow does not stick to the target, then there is not enough information to solve the problem. I suspect that even though the problem does not say completely inelastic, that is what you should assume (unless other information is given).
 

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