The discussion centers on solving the equation tan(x) + 3cot(x) = 4. The user successfully transformed the equation into tan^2(x) - 4tan(x) + 3 = 0, yielding solutions tan(x) = 1 and tan(x) = 3. For tan(x) = 1, the solutions are expressed as π/4 + nπ, where n is an integer. The discussion clarifies that tan^-1(3) cannot be expressed in terms of π, and users are advised to leave it in its original form.
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lovemake1 said:how would we represent tan^-1(3) interms of radians ?
calculators are not allowed in our school, is there a way ?
"pi/4 +180n" -> Don't mix degree and radian measure. Also, state what "n" is. You should writelovemake1 said:im not sure about tan = 3, but for tan = 1 , pi/4 +180n,
is this correct? if it is how would i go about findin solutions for tan=3.
No, you still need both solutions. The other could be written aslovemake1 said:hmm..
so we just find solutions for tan = 1 ?
lovemake1 said:tan^-1(3) + npi
how do you write that interms of pi?
i've never seen anything like that. could you please give me an example?
lovemake1 said:ok, just to make sure.. are my previous steps correct?
just to double check. thanks