Inequality of arithmetic and geometric means

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SUMMARY

The discussion focuses on maximizing the expression 2(√(1-a^2)) + 2a using the Inequality of Arithmetic and Geometric Means (AM-GM). Participants suggest that the maximum occurs at critical points derived from the derivative f'(a) = -2(1-a^2)^{-1/2} + 2, which is zero at a = 0. The analysis also reveals that the expression can be interpreted geometrically as an ellipse, providing a visual understanding of the problem. Ultimately, the AM-GM inequality can be applied by relating the components of the expression to their arithmetic and geometric means.

PREREQUISITES
  • Understanding of calculus, specifically derivatives and critical points
  • Familiarity with the Inequality of Arithmetic and Geometric Means
  • Basic algebraic manipulation skills
  • Knowledge of geometric interpretations of algebraic expressions
NEXT STEPS
  • Study the application of the Inequality of Arithmetic and Geometric Means in optimization problems
  • Learn how to find and analyze critical points using derivatives
  • Explore geometric interpretations of algebraic expressions, particularly ellipses
  • Practice solving similar maximization problems involving calculus and inequalities
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Students and enthusiasts of mathematics, particularly those interested in calculus, optimization techniques, and the application of inequalities in problem-solving.

Numeriprimi
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Hey! I have this: 2(√(1-a^2 ))+ 2a
How to determine the maximum value of this?

I think good for this is Inequality of arithmetic and geometric means, but I don't know how use this, because I don't calculate with this yet.

So, have you got any ideas?



Poor Czech Numeriprimi... If you don't understand my primitive English, write, I will try to write this better ;-)
 
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Hey! I have this: 2(√(1-a^2 ))+ 2a
How to determine the maximum value of this?

Could be a Calculus derivative problem. Does this f(a)=2(√(1-a^2 ))+ 2a have a maximum or minimum?
 
Carrying that farther f(a)= 2(1- a^2)^{1/2}+ 2a has derivative f'(a)= -2(1- a^2)^{-1/2}+ 2. Any maximum (or minimum) must occur where that derivative is 0 or does not exist. It does not exist when a= 1 or -1 because in that case we have a 0 in the denominator. It is 0 when \sqrt{1- a^2}= 1 or a= 0.

Check the values of 2\sqrt{1- a^2}+ 2a at x= -1, 0, and 1 to see which is the maximum value.

Another way to look at this is to see that if y= 2\sqrt{1- a^2}+ 2a then y- 2a= 2\sqrt{1- a^2} and so y^2- 4ay+ 4a^2= 4- 4a^2 or 8a^2- 4ay+ y^2= 4 which is the graph of an ellipse with major and minor axes rotated from the coordinate axes.
 
Please, derivate no... I still have a few years time to learn this.
I need to use Inequality of arithmetic and geometric means, bud how?
 
Your expression has two parts, ##2\sqrt{1-a^2}## amd ##2a##.

If you are supposed to use arithmetic and geometric means, you need to find some quantities that give those arithmetic and geometric means.

For example if the quantities are ##x## and ##y## and the arithmetic mean is ##2a##, you have the equation ##(x+y)/2 = 2a##

And you have another equation for the geometric mean ...
 
Yes, i have this: n=4
And what now?
 

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