# Inertial and Non-Inertial Frames of Reference Question

• Kaos_Griever
In summary, the problem involves a rubber stopper suspended by a string from a subway car traveling eastward. As the car slows down, the stopper and string hang at an angle of 13 degrees from the vertical. The acceleration of the train can be determined by using the formula a = g*tan(theta) and the magnitude of tension in the string can be found using the formula T = (m*g)/cos(theta). The final simplified solution for acceleration is a = g*tan(theta) and the tension in the string is T = m*g.

## Homework Statement

A rubber stopper of mass 25g is suspended by string from a handrail of a subway car traveling directly eastward. As the subway train nears a station, it begins to slow down, causing the stopper and string to hang at an angle of 13 degrees from the vertical. What is the acceleration of the train? Determine the magnitude of the tension in the string.

The attempt at a solution
Tension of String = (mass)(9.81) / cos 13 degrees
The Horizontal component of Tension = [(mass)(9.81) / cos 13 degrees] sin 13 degrees = (mass)(acceleration)
a = [[(mass)(9.81) / cos 13 degrees] sin 13 degrees] / mass

That works. But simplify that answer!

I'm not sure how to simplify the answer because I do not have many values to use...

You have everything you need.

Cancel what can be canceled; use a single trig expression. Then evaluate to get the numerical answer.

Thank you very much! =D It took me a while to understand it.. I thought what I was doing was wrong.

FYI, here's how I would do it:

Horizontal forces:
$$T\sin\theta = ma$$

Vertical forces:
$$T\cos\theta = mg$$

Combine (divide one by the other) to get:
$$a = g\tan\theta$$

Oh, thanks! I really appreciate your help.