Inertial & Gravitational Mass: When Do They Differ?

In summary: No. Velocity is not an invariant, just as "at rest" is not an invariant.If 2 particles are at rest, one then moves around wildly and is then brought back to rest with respect to the other particle, isn’t it now younger than the other particle that had a shorter world line or in plain language younger than the particle that had “less velocity?” Isn’t the “age” of the particle a function of its velocity?Although it can be expressed as a functional of the velocity, it is an invariant quantity. However, you have misunderstood what it means to have a short world-line. The length of your world-line is the amount that you have
  • #1
jeremyfiennes
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Under what circumstances are they different?
Under what circumstances are they different?
 
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  • #3
In Newtonian theory, the two are completely separate concepts that just happen to be identical for no clear reason. This suggests a common origin between inertial forces and gravitational forces, but Newtonian theory can't account for why they are the same.

In General relativity, the principle of equivalence basically assumes that they are the same, so the identity is part of the theory. This assumption is based on a fair number of experimental observations (look up 'tests of the equivalence principle'). As such, there is no need to distinguish between inertial and gravitatioanl mass in General relativity.

This is slightly oversimplified, in particular I haven't adressed the subtleities in the Principle of Equivalence, such as the weak, strong, and Einstein variants. But it should be a good start.
 
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  • #4
My question came from a comment I read in Hatch, R.R. (2007) "A New Theory of Gravity", Physics Essays 20:1 "Inertial and gravitational mass diverge in value as a function of velocity." So he is wrong?
Thanks.
 
  • #5
jeremyfiennes said:
Hatch, R.R. (2007) "A New Theory of Gravity", Physics Essays 20:1

This, from the abstract, looks like a speculative paper from a questionable journal. It appears to be behind a paywall so I can't read the full paper.

Also, if you are asking a question based on something you read in a reference, you should give that reference in the OP.

jeremyfiennes said:
"Inertial and gravitational mass diverge in value as a function of velocity." So he is wrong?

No such effect has ever been observed experimentally. The current limits are pretty tight:

https://en.wikipedia.org/wiki/Equivalence_principle#Tests_of_the_weak_equivalence_principle
Also, since in relativity "velocity" has no invariant meaning, it's hard to see what "as a function of velocity" would mean physically.
 
  • #6
PeterDonis said:
Also, since in relativity "velocity" has no invariant meaning, it's hard to see what "as a function of velocity" would mean physically.

I’m confused by this as I believe it was explained in a recent time dilation thread that the time dilation experienced by a particle has dependence on the length of its world line compared to the length of another particle’s world line, when the particles are separated and then brought back together.
 
  • #7
metastable said:
the time dilation experienced by a particle has dependence on the length of its world line compared to the length of another particle’s world line, when the particles are separated and then brought back together

This is true. Why does it make you confused about what I said about velocity?
 
  • #8
If 2 particles are at rest, one then moves around wildly and is then brought back to rest with respect to the other particle, isn’t it now younger than the other particle that had a shorter world line or in plain language younger than the particle that had “less velocity?” Isn’t the “age” of the particle a function of its velocity?
 
  • #9
metastable said:
Isn’t the “age” of the particle a function of its velocity?

No. Velocity is not an invariant, just as "at rest" is not an invariant.
 
  • #10
metastable said:
If 2 particles are at rest, one then moves around wildly and is then brought back to rest with respect to the other particle, isn’t it now younger than the other particle that had a shorter world line or in plain language younger than the particle that had “less velocity?” Isn’t the “age” of the particle a function of its velocity?
Although it can be expressed as a functional of the velocity, it is an invariant quantity. However, you have misunderstood what it means to have a short world-line. The length of your world-line is the amount that you have aged. Hence, the shorter the world-line, the younger the object. Now, geometry in spacetime does not work the same way as geometry works in a "normal" space so the object moving around actually has a shorter world-line.
 
  • #11
metastable said:
If 2 particles are at rest, one then moves around wildly and is then brought back to rest with respect to the other particle, isn’t it now younger than the other particle
If, by "at rest", you actually mean "at rest in an inertial frame" then yes. Otherwise, maybe. It depends on what you mean by "at rest".
metastable said:
isn’t it now younger than the other particle that had a shorter world line or in plain language younger than the particle that had “less velocity?”
The length (more precisely, the interval) of the worldline is the key thing here, the invariant on which everyone will agree. Whether or not an object had "more" or "less" velocity is dependent on your choice of frame.
metastable said:
Isn’t the “age” of the particle a function of its velocity?
If you pick a frame then you can express the length of the worldline as a function solely of the velocity of the particle with respect to the frame. The form of the expression depends on your choice of frame, however, which is how the result can be the same even if you choose to use a frame where the velocity of the "wildly moving" one is zero.
 
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  • #12
metastable said:
If 2 particles are at rest, one then moves around wildly and is then brought back to rest with respect to the other particle, isn’t it now younger than the other particle that had a shorter world line or in plain language younger than the particle that had “less velocity?” Isn’t the “age” of the particle a function of its velocity?

The following comment is not relevant to the issue of inertial versus gravitational mass, but I would like to suggest that interpreting time dilation as "speed slowing aging" is a bad way to think about it.

There are two different notions of "time" in Special Relativity: (1) coordinate time is one dimension of 4-dimensional spacetime, and as such is much like the other three spatial dimensions, (2) proper time is a measure of a traveler's progress through spacetime. If you travel for one hour, according to your watch, you will end up in a different point in spacetime than when you started. Exactly where you end up in spacetime depends on your proper velocity. How much your x-coordinate changes depends on the x-component of your velocity, ##\dfrac{\Delta x}{\Delta \tau}## (where ##\tau## is the time on your watch). How much your t-coordinate changes depends on the t-component of your velocity, ##\dfrac{\Delta t}{\Delta \tau}##.
 
  • #13
stevendaryl said:
How much your t-coordinate changes depends on the t-component of your velocity
If I understand this correctly,"not accelerating" an unstable particle can "hasten" its loss of inertial mass.
 
  • #14
metastable said:
If I understand this correctly,"not accelerating" an unstable particle can "hasten" its loss of inertial mass.

No, I wasn't saying that. What I was saying was that if you're traveling to a particular point in spacetime--say, the point "Seattle, July 1, 2019", you can get there quicker (according to your watch) if you have a larger 4-velocity.

The appropriate notion of "time" to use when measuring such things as decay rates is proper time, not coordinate time.
 
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stevendaryl said:
larger 4-velocity.
Should that say "3-velocity"? 4-velocity is normalised to ##c##. Or am I missing your point?
 
  • #16
stevendaryl said:
you can get there quicker (according to your watch) if you have a larger 4-velocity.

I assume that, as @Ibix suggested, you mean a larger 3-velocity. 4-velocity is a unit vector; all 4-velocities are "the same size".
 
  • #17
Ibix said:
Should that say "3-velocity"? 4-velocity is normalised to ##c##. Or am I missing your point?

Yes, that's what I meant.
 
  • #18
stevendaryl said:
say, the point "Seattle, July 1, 2019", you can get there quicker (according to your watch) if you have a larger 43-velocity.
Although you’ll also have to start later and closer.
 
  • #19
Nugatory said:
Although you’ll also have to start later and closer.

If you want to keep a constant 4-velocity, yes. But you can zig-zag to Seattle, July 1, 2019 and get there in arbitrarily small amount of proper time.
 

FAQ: Inertial & Gravitational Mass: When Do They Differ?

What is the difference between inertial and gravitational mass?

Inertial mass is a measure of an object's resistance to changes in motion, while gravitational mass is a measure of the strength of an object's gravitational pull. In other words, inertial mass determines how an object responds to a force, while gravitational mass determines how much force an object exerts on other objects.

Can an object have different values for its inertial and gravitational mass?

Yes, an object can have different values for its inertial and gravitational mass. This is because they are measured differently and can have different physical properties, such as density or composition, that affect their values.

When do inertial and gravitational mass differ?

In general, inertial and gravitational mass are considered to be equivalent, meaning they have the same value. However, there are theories, such as Einstein's theory of general relativity, that suggest they may differ in extreme conditions, such as near a black hole.

How do scientists measure inertial and gravitational mass?

Inertial mass can be measured by applying a known force to an object and measuring its acceleration. Gravitational mass can be measured by observing the gravitational attraction between two objects of known mass.

Why is the concept of inertial and gravitational mass important in physics?

The concept of inertial and gravitational mass is important in physics because it helps us understand how objects behave under the influence of forces and gravity. It also plays a crucial role in theories such as Newton's laws of motion and Einstein's theory of general relativity.

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