DrStupid
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TurtleMeister said:I've never seen that before.
I'm sure you have seen that before:
For constant inertial mass mi Newton's second law of motion results in
F = m_i \cdot a
and according to his law of gravitation the gravitational force acting on a point mass at position r with the gravitational mass mg (exerted by a point mass Mg at position R) is
F = \frac{{G \cdot M_g \cdot m_g \cdot \left( {R - r} \right)}}{{\left| {R - r} \right|^3 }}
With mg = mi this results in the acceleration
a = \frac{{G \cdot M_g \cdot \left( {R - r} \right)}}{{\left| {R - r} \right|^3 }}
which is obviously not only independent from the composition and mass of the body but also from it's velocity. In the publication I linked above Olson and Guarino demonstrated that this is not always the case. The description of the hyperbolic trajectory of a relativistic particle within classical mechanics requires a violation of the Newtonian equivalence principle whereas the Galilean equivalence principle still holds (because the relativistic trajectory is identical for all bodies starting from the same position with the same velocity). That's one of the reasons why the classical definitions of inertial and gravitational mass can't be used in GR.
Another (more fundamental) reason is the incompatibility of Newton's law of gravitation (which the classical gravitational mass is based on). It can't be used in SR because it is not consistent with Lorentz transformation and in GR it makes no sense at all because GR is a theory of gravitation itself and does not need any additional laws for gravity.
That's why I repeatedly asked for the definition of inertial and gravitational mass in GR but I didn't get an answer so far. Without such definitions "inertial mass = gravitational mass" is either false or pointless in GR.
TurtleMeister said:I've always thought that Newton's experiments were just confirming Galileo's.
Of course they were. His experiments wasn't suitable for the detection of relativistic effects and within its scope classical mechanics is full consistent with the Galilean equivalence principle (I guess that's what the Newtonian equivalence principle was intended for).
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