Infinite energy states for an harmonic oscillator?

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SUMMARY

The discussion centers on the existence of infinite-energy states for a harmonic oscillator with a normalizable wave function, specifically the function ##\Psi(x) = \frac{1}{1+x^2}##. This wave function is square-integrable but does not lie within the domain of the harmonic oscillator Hamiltonian, which is unbounded. The key conclusion is that the unbounded nature of the Hamiltonian allows for the existence of such states, despite their counter-intuitive implications in quantum mechanics.

PREREQUISITES
  • Understanding of quantum mechanics principles, specifically harmonic oscillators.
  • Familiarity with wave functions and their properties, including normalizability and square-integrability.
  • Knowledge of Hamiltonian operators and their role in quantum systems.
  • Basic grasp of unbounded operators in the context of physical observables.
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  • Research the implications of unbounded operators in quantum mechanics.
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Quantum physicists, students of quantum mechanics, and researchers exploring advanced topics in wave functions and harmonic oscillators.

Catria
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So, I've read conference proceedings and they appear to talk about counter-intuitive it was to create an infinite-energy state for the harmonic oscillator with a normalizable wave function (i.e. a linear combination of eigenstates). How exactly could those even exist in the first place?
 
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Try ##\Psi(x) = \frac{1}{1+x^2}##. It's clearly square-integrable, but if you apply the harmonic oscilllator Hamiltonian, you get a function that converges to a non-zero constant for ##x\rightarrow\infty##. The reason for why there can be such states is that the Hamiltonian of the harmonic oscillator is unbounded. The ##\Psi## I mentioned doesn't lie in the domain of ##\hat H##. Most physical observables correspond to unbounded operators.
 

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