Convergence or Divergence of Infinite Series: Methods and Examples

Click For Summary
The discussion focuses on determining the convergence or divergence of the series Ʃ(1/(n*ln(n)^2 - n)) from n = 1 to infinity. Participants initially struggle with the comparison test due to the series being negative for the first two terms. It is clarified that the convergence or divergence is determined by the tail of the series, not the initial terms. The Limit Comparison Test requires positive sequences, but it is noted that analyzing the series from n = 3 is sufficient. Ultimately, the integral test is successfully applied from n = 3 to infinity, confirming that the series converges.
physicsernaw
Messages
41
Reaction score
0

Homework Statement



Determine convergence or divergence using any method covered so far*:

Ʃ(1/(n*ln(n)^2 - n)) from n = 1 to infinity*The methods are the following:

- Dichotomy for positive series (if the partial sums are bounded above and the series is positive, the series converges)

- Integral Test

- Convergence of p-Series

- Comparison test

- Limit Comparison Test

Homework Equations



n/a

The Attempt at a Solution



The series is negative for n = 1 and 2, so I am left with Comparison test but I am having trouble determining what sequence to compare to. I am not "seeing" it.
 
Physics news on Phys.org
physicsernaw said:

Homework Statement



Determine convergence or divergence using any method covered so far*:

Ʃ(1/(n*ln(n)^2 - n)) from n = 1 to infinity

Is that denominator ##n\ln^2(n) -n## or ##n\ln (n^2)-n##?
*The methods are the following:

- Dichotomy for positive series (if the partial sums are bounded above and the series is positive, the series converges)

- Integral Test

- Convergence of p-Series

- Comparison test

- Limit Comparison Test

Homework Equations



n/a

The Attempt at a Solution



The series is negative for n = 1 and 2, so I am left with Comparison test but I am having trouble determining what sequence to compare to. I am not "seeing" it.

It doesn't matter if the first few terms of the series are negative. It is the tail end of the series that determines convergence or divergence. So don't rule out the other methods.
 
The denominator is the first one you posted, n*(ln(n))^2 - n.

In my book for the Limit Comparison Test it states "Let a[n] and b[n] be positive sequences." I assumed that "positive sequences" meant positive for all n [1, infinity). So it is really saying that if the sequence converges to a positive value or diverges "positively" than one can use the Limit Comp test on these sequences? Or am I still off base
 
physicsernaw said:
The denominator is the first one you posted, n*(ln(n))^2 - n.

In my book for the Limit Comparison Test it states "Let a[n] and b[n] be positive sequences." I assumed that "positive sequences" meant positive for all n [1, infinity). So it is really saying that if the sequence converges to a positive value or diverges "positively" than one can use the Limit Comp test on these sequences? Or am I still off base

If ##\sum_{n=3}^\infty a_n## converges or diverges, adding ##a_1+a_2## to it won't change the convergence or divergence. So analyze the sum from 3. I would suggest a combination of comparison and integral tests.
 
  • Like
Likes 1 person
Ahh I see thanks for clarifying. I will reattempt the problem.

EDIT: Got it by simply using integral test from n=3 to infinity. The integral converges so the series must as well. Thanks LCKurtz.
 
Last edited:
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

Similar threads

  • · Replies 3 ·
Replies
3
Views
1K
  • · Replies 4 ·
Replies
4
Views
1K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 14 ·
Replies
14
Views
2K
Replies
8
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K