Initial Velocity of 1.52 m High Jump Record

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To calculate the initial velocity needed for a high jump of 1.52 meters, consider the acceleration due to gravity, which is 9.8 m/s². At the peak of the jump, the jumper's velocity is zero, providing key data points for the calculation. The discussion highlights the importance of understanding the physics involved, particularly the relationship between height, initial velocity, and gravitational acceleration. After some clarification, the original poster successfully determined the initial velocity required for the jump. This problem illustrates the application of kinematic equations in real-world scenarios.
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Homework Statement



Assuming the best high jump record from a standing position in a school was 1.52 m, what initial velocity was needed for this jump? neglect any sideways motion.

Homework Equations



velocity equation


The Attempt at a Solution



I don't really understand how to do the question? Is there a knowledge part involved that I can't figure out? There is only one given data?
 
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That is not true. Think about the situation more thoroughly. You know that his acceleration is 9.8m/s downwards. You also know that his 1.52 metres is achieved at the peak of his jump, at which time his velocity will be 0. So now you 3 pieces of information.
 
dacruick said:
That is not true. Think about the situation more thoroughly. You know that his acceleration is 9.8m/s downwards. You also know that his 1.52 metres is achieved at the peak of his jump, at which time his velocity will be 0. So now you 3 pieces of information.

Thanks I got the answer :D & How to do it :D
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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