Initial Velocity Question

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SUMMARY

The discussion centers on calculating the initial velocity of a water balloon launched vertically using conservation of energy principles and kinematic equations. Participants explore the equation VFy^2 = VOy^2 + 2a * Displacement Y to derive the initial velocity (Vo) without a stopwatch. The final velocity (VFy) is established as 0 m/s at the peak of the trajectory, and acceleration due to gravity (a) is set at -9.81 m/s². The conversation emphasizes the importance of understanding the relationship between height and velocity, particularly that velocity increases with the square root of height.

PREREQUISITES
  • Understanding of kinematic equations, specifically VFy^2 = VOy^2 + 2a * Displacement Y
  • Familiarity with concepts of vertical motion and gravity (9.81 m/s²)
  • Knowledge of trigonometric functions (sine, cosine, tangent) for angle measurement
  • Basic principles of conservation of energy in physics
NEXT STEPS
  • Learn how to apply the kinematic equation for different heights and calculate initial velocities
  • Research the use of protractors in measuring angles and heights in projectile motion
  • Explore the relationship between height and velocity in vertical motion using square root functions
  • Investigate practical methods for measuring vertical displacement in experiments
USEFUL FOR

Students in physics courses, educators conducting projectile motion experiments, and anyone interested in understanding the principles of vertical motion and energy conservation.

  • #61
Yeah, my last post indicated that i could use a protractor , but after googling , i do not know how to measure displacement or distance for a vertical length using one

Would you happen to have a tutorial or maybe some helpful tips on this process?
 
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  • #62
Have you learned about sin, cos, and tangent? The protractor can be used to measure the angle between the ground and the balloon, if you stand a distance away from the launcher. Measure this distance as well, and draw a right triangle. You'll have the bottom of the right triangle, an acute angle, and of course, the 90 degree angle at the launcher. Simple right triangle trig can be used to solve for the vertical side of the triangle.
 
  • #63
ok thanks drpizza, yeah i have learned about sin,cos tan, though this will be hard measuring it in a matter of seconds
 

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