- #51

- 3,042

- 15

Do you see this?

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- Thread starter MaNiFeST
- Start date

- #51

- 3,042

- 15

Do you see this?

- #52

- 36

- 0

sorry i dont really follow

- #53

- 3,042

- 15

10m/5m = 2 <-- you DOUBLED the height it stopped at

14.007/9.9045= 1.4142 <--does NOT, does NOT, does NOT DOUBLE.

1.4142 = sqrt(2) <--it changes by the square ROOT of the change in height.

- #54

- 3,042

- 15

Try it for a different change in heights and see if it works.

- #55

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15/5 = 3

9904*sqrt(3) = 17.154

It works!

Thanks dude

9904*sqrt(3) = 17.154

It works!

Thanks dude

- #56

- 3,042

- 15

You will get your bonus. You solved this on your own.

- #57

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I didnt really do this on my own, but thanks dude, you really helped me!

Yeah i do understand this, ill have to remember last part, but tricky

Yeah i do understand this, ill have to remember last part, but tricky

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- #58

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- #59

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I tried searching google but didnt really find anything, do you have a helpful tutorial or maybe some tips on using a protractor to determine the height of something launched 90 degress into the air?

- #60

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Manifest, I was going to suggest to you that you could stand at a distance from the waterballoon slingshot, then aim the meter stick toward the highest point the balloon reaches. Constructing a smaller triangle from where the meter stick is pointing, you could use similar triangles to calculate the maximum height of the waterballoon. However, now that you're allowed to use a protractor, right triangle trig simplifies the work you're going to have to do (slightly).

btw, I appreciate this thread... after calculating an initial velocity, my students then have to calculate a horizontal range after pulling an angle out of a hat. (I stand at their calculate point, getting soaked if all goes well.) Students are notoriously horrible at getting accurate times with a stopwatch.

You'll definitely want to use the formula that cyrusabdollahi led you to. However, I agree with your skepticism toward getting credit for suggesting that you measure the vertical displacement with a meter stick.

- #61

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Would you happen to have a tutorial or maybe some helpful tips on this process?

- #62

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- #63

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