Instantaneous rate of change homework

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For the function f(x)=3x^2-1, the average rate of change on the interval [1,3] is calculated to be 12. The derivative of the function, f'(x)=6x, is then set equal to this average rate of change. Solving the equation 12=6x yields x=2. This indicates that at x=2, the instantaneous rate of change matches the average rate of change over the specified interval. The discussion also suggests reviewing the Mean Value Theorem for further understanding.
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Homework Statement



For the function f(x)=3x^2-1, for what x values is the instantaneous rate of change equal to the average rate of change on the interval [1,3]


Homework Equations





The Attempt at a Solution

 
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1) first find the average rate of change on the interval (1,3)

2) set that number equal to the derivative of the function and solve for x1) Finding the avg rate of change over the interval 1,3

f(1) = 2
f(3) = 26

so we have (1,2) and (3,26)
the slope give the rate of change so to find the slope between these points
we use the slope formula which gives us 12

2) f `(x) = 3x^2+1

average rate of change = 6x

12 = 6x

x = 2

so when x = 2 in the instantaneous rate of change, it equals the average rate on the
interval [1,3]. notice its between 1 and 3.
 


Just to add you might want to look-up the mean value theorem.
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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