Instantaneous Velocity from the graph

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SUMMARY

The discussion focuses on calculating instantaneous velocity from a distance-time graph using the formula for instantaneous velocity, lim Δv=(Δx/Δt) as t approaches 0. Participants clarify that on a linear graph, the slope represents both average and instantaneous velocity, as there are no curves present. The correct interpretation of points on the graph is emphasized, particularly noting that at x=1, the value of y is 5, not 4. The conversation concludes that for linear functions like f(x)=4x, the slope directly correlates to velocity.

PREREQUISITES
  • Understanding of distance-time graphs
  • Knowledge of limits in calculus
  • Familiarity with the concept of slope
  • Basic algebra for interpreting linear equations
NEXT STEPS
  • Study the concept of limits in calculus for deeper insights into instantaneous rates of change
  • Explore the relationship between slope and velocity in various types of graphs
  • Learn how to differentiate between average and instantaneous velocity in different scenarios
  • Investigate linear functions and their graphical representations in physics
USEFUL FOR

Students studying physics, particularly those focusing on kinematics, educators teaching graph interpretation, and anyone looking to understand the relationship between distance, time, and velocity.

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Homework Statement



The problem is finding the instantaneous velocity during certain time intervals from the graph.
p2-03.gif


Examples of time intervals: 1.1s, 7.4s, 2.7s

Homework Equations



I know this is the formula for finding the instantaneous velocity

lim Δv=(Δx/Δt)
t->0

The Attempt at a Solution



I tried locating the points on the curve, by taking two obvious points like 1 on the x and 4 on the y and then making a cross multiplication to find the y in terms of 1.1 and then dividing by the T, since I do not think drawing a tangent to the point is possible here. So, should I use the equation somehow? I made several attempts but they all turned out to be incorrect.
 
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According to your graph, there are no "curves", but only straight lines. Recall that on a distance-time graph, the slope is the velocity. The lines' slopes are easy to calculate because they intersect on reasonable numbers.

So, the slope at 1.1 sec would be equal to the slope at 1 sec or any time within 0-2 seconds.

Also, at x=1, y does not equal 4, but actually equals 5.
 
Shootertrex said:
According to your graph, there are no "curves", but only straight lines. Recall that on a distance-time graph, the slope is the velocity. The lines' slopes are easy to calculate because they intersect on reasonable numbers.

So, the slope at 1.1 sec would be equal to the slope at 1 sec or any time within 0-2 seconds.

Also, at x=1, y does not equal 4, but actually equals 5.

But isn't the average velocity different than the instantaneous one? Like, I know the slope can represent the average velocity, but is that true on this graph for instantaneous velocity too because it's not a curve?
 
Instantaneous velocity is the slope of the line tangent to a point on a curve. Is there really a way to make a line that will be tangent to another line? Not really. Let's say that you can. This 'tangent' line have the same slope as the line it is tangent to, and is actually the same line.

Lets say that f(x)=4x will be the equation that illustrates the distance of an object. Velocity is the change in distance over the change in time. The change in distance for this function is the slope of the line. Therefore the slope of this line will equal the velocity, both average and instantaneous.
 
Yes, that is true. Thank you VERY much for that ^^
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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