Intake Temperature for a 40.2% Efficient Carnot Engine

[shar_p]

Homework Statement

The exhaust temperature of a Carnot heat engine is 401◦ C.
What is the intake temperature if the efficiency of the engine is 40.2 %?
Answer in units of ◦ C.

Homework Equations

e = 1 - Tc/Th (all in Kelvin)

The Attempt at a Solution

0.402 = 1 - Tc/ (401+273) = 1 - Tc/674
Tc = 0.598 * 674 = 403.052
Tc in C = 403.052-273 = 130.052

But somehow this answer seems to be wrong on the quest. This is my last problem ..please help? What am I doing wrong? Am I missing something?

 

[rock.freak667]

You were given T_c to get T_h, not the other way around like you did.

 

[shar_p]

Thanks .. that worked.