Integer Sequence: Solve & Generate Terms

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    Integer Sequence
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The integer sequence begins with the terms 2, 4, 16, 256, and 65536, which can be expressed as powers of 2: 2^1, 2^2, 2^4, 2^8, and 2^16. The pattern involves each exponent being a power of 2, specifically 2 raised to the power of the previous exponent. To find the nth term, the formula is 2^(2^(n-1)). This approach allows for efficient calculation of any term in the sequence without sequential multiplication. Understanding the exponent pattern simplifies generating terms significantly.
Madonna M.
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1. Homework Statement

Provide a simple formula or rule that generates the terms of an integer sequence that begins with :

* 2,4,16,256,65536,...


3. The Attempt at a Solution

I have tried a lot to solve it but i ended up with nothing,although i know that finding a term in the following sequence depends on multiplying the number by itself. For example if i want to get the 3rd term i will multiply the 2nd term by itself (4*4)=16 and same goes to the rest of the sequence,but what about if i want to get the 100th term,of course i won't multiply each term by itself until i reach the needed term,a formula or a rule would be more helpful.

Thanks in advance :)
 
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think about what exponents of 2 are needed to give that sequence.
 
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could you give me more clear clue please?? :)
 
Madonna M. said:
could you give me more clear clue please?? :)

Your sequence is ##2^1, 2^2, 2^4, 2^8, 2^{16}, ...##.
See the pattern?
 
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well,do you mean that every time am going to multiply the power of the previous term by 2 to get the next one?
 
Ahaa i got it thanks a lot,i think it would be 2^(2^(n-1))
 
Good! :)
 

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