Graduate Integral -- Beta function, Bessel function?

Click For Summary
The integral of sin cubed from 0 to pi can be expressed using the Beta function, specifically B(1/2, 1/2), which equals pi. The calculation shows that the integral evaluates to 4π/3, confirming the relationship with the Beta function. Additionally, the discussion explores the potential connection to Bessel functions, although the primary focus remains on the Beta function representation. The integral's transformation highlights the interplay between trigonometric integrals and special functions. Overall, the integral can indeed be represented in terms of the Beta function.
LagrangeEuler
Messages
711
Reaction score
22
Integral
\int^{\pi}_0\sin^3xdx=\int^{\pi}_0\sin x \sin^2xdx=\int^{\pi}_0\sin x (1-\cos^2 x)dx=\frac{4 \pi}{3}
Is it possible to write integral ##\int^{\pi}_0\sin^3xdx## in form of Beta function, or even Bessel function?
 
Physics news on Phys.org
Since B(\frac12,\frac12) = \pi you have <br /> \int_0^{\pi} \sin^3 x\,dx = \tfrac43B(\tfrac12,\tfrac12) = \tfrac43 \int_0^1 u^{-1/2}(1 - u)^{-1/2}\,du.
 

Similar threads

  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K