Integral Calculus Homework: Mean & RMS Voltage

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Homework Help Overview

The discussion revolves around calculating the mean and root mean square (RMS) values of an AC voltage function, specifically V = 4cos(2θ), using integral calculus over the interval from 0 to 2π. Participants are exploring the application of integral calculus to find these values.

Discussion Character

  • Exploratory, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants are attempting to set up the integral for the mean value calculation and are questioning the correct application of limits for the definite integral. There is also a discussion about the expression for the function being integrated.

Discussion Status

Some participants have provided guidance on using the limits of integration and have referenced the mean value formula. There is an ongoing exploration of the correct interpretation of the function and the integration process.

Contextual Notes

The original poster has referenced the need to use specific identities and has indicated the limits of integration, but there seems to be some confusion regarding the setup of the integral and the function being analyzed.

maali5
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Homework Statement



A generated AC voltage has a value given by V = 4cos2θ.

You will need to use the identity cos^2⁡θ = 1/2(1+cos2θ)


a) Find the mean value of the voltage over a full cycle (0 ≤ θ ≤ 2π) using integral calculus

b) Find the r.m.s. value of the voltage over a full cycle (0 ≤ θ ≤ 2π) using integral calculus



Homework Equations





The Attempt at a Solution




4∫cos2x dx u = 2x du= 2dx du/2 = dx


4∫ cos u du

2 sin 2x +c



What is next now?
 
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maali5 said:

Homework Statement



A generated AC voltage has a value given by V = 4cos2θ.

You will need to use the identity cos^2⁡θ = 1/2(1+cos2θ)

a) Find the mean value of the voltage over a full cycle (0 ≤ θ ≤ 2π) using integral calculus

b) Find the r.m.s. value of the voltage over a full cycle (0 ≤ θ ≤ 2π) using integral calculus

Homework Equations



The Attempt at a Solution



4∫cos2x dx u = 2x du= 2dx du/2 = dx

[STRIKE]4[/STRIKE] 2∫ cos u du

2 sin 2x +c

What is next now?
Find the average over a full cycle.

The average (mean) value of function f(x) over the interval [a, b] is given by

[itex]\displaystyle f_\text{Mean}=\frac{\displaystyle \int_a^b{f(x)\,dx}}{b-a}\ .[/itex]
 
SammyS said:
Find the average over a full cycle.

The average (mean) value of function f(x) over the interval [a, b] is given by

[itex]\displaystyle f_\text{Mean}=\frac{\displaystyle \int_a^b{f(x)\,dx}}{b-a}\ .[/itex]


Where is the interval?

Is this f(x)? = 2 sin 2x +c
 
maali5 said:
Where is the interval?

Is this f(x)? = 2 sin 2x +c

Hello maali5,
The interval has been quoted in your question right?
(0 ≤ θ ≤ 2π)
You have to have a definite integral right?So you will have to plug in these limits.And then the use the expression quoted by SammyS with these limits.

regards
Yukoel
 

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