Proving Zero Result with Complex Conjugates and Dot Product

[Scootertaj]

Homework Statement

Show that the following = 0:
\int_{-\infty}^{+\infty} \! i*(\overline{d/dx(sin(x)du/dx})*u \, \mathrm{d} x + \int_{-\infty}^{+\infty} \! \overline{u}*(d/dx(sin(x)du/dx) \, \mathrm{d} x where \overline{u} = complex conjugate of u and * is the dot product.

2. Work so far
My thoughts: \int_{-\infty}^{+\infty} \! i*(\overline{d/dx(sin(x)du/dx})*u \, \mathrm{d} x + \int_{-\infty}^{+\infty} \! \overline{u}*(d/dx(sin(x)du/dx) \, \mathrm{d} x
=
\int_{-\infty}^{+\infty} \! -i*(d/dx(sin(x)du/dx)*u \, \mathrm{d} x + \int_{-\infty}^{+\infty} \! \overline{u}*(d/dx(sin(x)du/dx) \, \mathrm{d} x

But I don't even know if that's right.

 

[Scootertaj]

Bump.