Integral evaluated at +/- infinity

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    Infinity Integral
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SUMMARY

The integral \(\int^{+\infty}_{-\infty}{\frac{1}{(x^2 + d^2)^\frac{3}{2}}}dx\) is evaluated using the limit approach for improper integrals. The expression \(\frac{x}{d^2\sqrt{x^2 + d^2}}\) must be evaluated as \(x\) approaches \(\pm\infty\). The correct evaluation leads to the conclusion that the limit approaches 0, not infinity, due to the dominance of the denominator as \(x\) increases. Understanding this requires knowledge of limits in calculus.

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diffusion
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Ok, I'm trying to solve this physics problem and I've come to the following integral ([tex]d[/tex] is taken to be some constant):

1. [tex]\int^{+\infty}_{-\infty}{\frac{1}{(x^2 + d^2)^\frac{3}{2}}}dx[/tex]

Now, integrating this I am supposed to get

2. [tex]{\frac{x}{d^2\sqrt{x^2 + d^2}}}[/tex], evaluated at [tex]\pm\infty[/tex] (Sorry, don't know latex code for that).

I don't know how to evaluate this last step. It would seem I should either get 0 or infinity, but apparently that isn't the answer. Could anyone enlighten me?
 
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This is one reason why sloppiness can be bad. If you weren't thinking of it as "evaluate at infinity", you would have remembered that such improper integrals are limits... and you would have known to apply what you know about limits!
 
For large magnitude x, your expression (2.) is approx. x/[d2|x|]. You should be able to finish.
 

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