Integral from o to inf of sin(x/2)dx

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SUMMARY

The integral from 0 to infinity of sin(x/2)dx diverges. The discussion outlines the process of evaluating this integral by first taking the limit as a approaches infinity of the integral from 0 to a of sin(x/2)dx. The integration yields -cos(x/2) evaluated from 0 to a, leading to the limit expression -2cos(a/2) + 2. The conclusion is that the limit does not exist due to the oscillatory nature of the cosine function, confirming the divergence of the original integral.

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Integral from o to inf of sin(x/2)dx

First thing I did was ditch the infinity so it became:
lim as a-->inf of integral from 0 to a of sin(x/2)dx

next I integrated it:
lim as a approaches infin of -cos(x/2) evaluated from o to a

then I plugged in:
lima->inf of -2cos(a/2)+2(cos0)

My problem is that I don't know if cos of inf diverges of converges. I know that it occelates, but what does that count as? Or, am I missing a step in here or just messed up somewhere along way? If anyone has any suggestions, I would greatly appreciate it.
 
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You can't take the cosine of infinity. The limit of interest, lim a --> inf -2cos(a/2) does not exist, so your original integral diverges.
 


ok Thank you!
 

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