Integral involving product of derivatives of Legendre polynomials

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SUMMARY

The integral \(\int_{-1}^{1} (1-x^2) P_{n}^{'} P_m^{'} dx\) can be evaluated using integration by parts and the properties of Legendre polynomials. The key facts include the recurrence relation \(\left((1-x^2)P_n^\prime \right)^\prime=-n(n+1)P_n\) and the orthogonality condition \(\int_{-1}^1 P_m P_n \text{ dx}=\dfrac{2}{2n+1} \delta_{mn}\). Utilizing these relationships allows for a systematic approach to solving the integral effectively.

PREREQUISITES
  • Understanding of Legendre polynomials and their properties
  • Familiarity with integration by parts technique
  • Knowledge of recurrence relations for derivatives of Legendre polynomials
  • Basic concepts of orthogonality in polynomial functions
NEXT STEPS
  • Study the derivation and applications of Legendre polynomial recurrence relations
  • Explore advanced integration techniques involving special functions
  • Learn about the properties of orthogonal polynomials in mathematical physics
  • Investigate the use of Legendre polynomials in solving differential equations
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Mathematicians, physicists, and students studying mathematical methods in physics, particularly those focusing on special functions and orthogonal polynomials.

hanson
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Anyone how to evaluate this integral?

\int_{-1}^{1} (1-x^2) P_{n}^{'} P_m^{'} dx, where the primes represent derivative with respect to x?

I tried using different recurrence relations for derivatives of the Legendre polynomial, but it didn't get me anywhere...
 
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Use the facts

\left((1-x^2)P_n^\prime \right)^\prime=-n(n+1)P_n

and

\int_{-1}^1 P_m P_n \text{ dx}=\dfrac{2}{2n+1} \delta_{mn}

to integrate by parts

or just use

P_n=\frac{1}{(2n)!} \dfrac{d^n}{dx^n} (x^2-1)^n
 
Last edited:
Thank you very much!
 

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