- #1
sparkle123
- 175
- 0
Why is int(1/(1-x))=-ln(abs(1-x))?
If you substitute u=1-x
then
int(u)=ln(abs(u))=ln(abs(1-x))
Also, in this question you're trying to find the particular solution y=f(x) to the given differential euqation with initial conditions
f(-1)=2
dy/dx=6x^2-x^2y
d^2y/dx^2=-12.
So i get to:
ln(abs( 6 − y)) = − 1/3 x^3 − (1/3 − ln 4)
Why does the solution say I can remove absolute values to get:
y=6-4e^(-1/3(x^3+1)) ?
Thanks!
If you substitute u=1-x
then
int(u)=ln(abs(u))=ln(abs(1-x))
Also, in this question you're trying to find the particular solution y=f(x) to the given differential euqation with initial conditions
f(-1)=2
dy/dx=6x^2-x^2y
d^2y/dx^2=-12.
So i get to:
ln(abs( 6 − y)) = − 1/3 x^3 − (1/3 − ln 4)
Why does the solution say I can remove absolute values to get:
y=6-4e^(-1/3(x^3+1)) ?
Thanks!