Integral of F on Curve C: Evaluate

[Tom McCurdy]

The problem:

Evaluate the integral
$$\oint_{c} Fdr$$ for $$F = (2xy^4)i+(2x^2y^3)j$$ on the curve C consisting of the x-axis from x=0 to x=1, the parabola y=1-x^2 up to the y-axis, and the y-axis down to the origin

Here is what I triedF(x,y)=$$<2xy^4,2x^2y^3>$$$$\int\int_{D} =[(2x^2y^3)*\frac{\partial}{\partial x}-(2xy^4)\frac{\partial}{\partial y}] dA$$= $$\int_{0}^{1} \int_{1-x^2}^{0} [4xy^3-8xy^3] dy dx$$=1/10

 

[Tom McCurdy]

Ok I have redone this problem... multiple times... and now I am getting

-1/10

can someone confirm this for me, I am out of tries on my submission so I need to be sure when I submit this problem

 

[Tom McCurdy]

alright I solved it nevermind

 

[Office_Shredder]

I am so confused by the double integral