I was taking the integral of the secant function. Twice... The first one is simple, but what is the integral of ln(secx + tanx)dx? I've tried a few things, the first being integration by parts with u = ln(secx + tanx+) and dv = dx This just cancels in the end to 0 = 0 I also rewrote it as int[ln(1+sinx) - ln(cosx)]dx but that doesn't seem to be any easier. Any suggestion would be greatly appreciated.