Integral of statistical mechanics

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SUMMARY

The integral \(\int ^{\infty}_0 \frac{x^3}{e^x+1} dx\) is a common problem in statistical mechanics, specifically related to Fermi-Dirac statistics. The discussion highlights the relationship between Fermi and Bose functions, noting that the difference between them can be expressed as \(1/(e^x+1) - 1/(e^x-1) = 2/(e^{2x}-1)\). This relationship can be utilized to derive the Bose form from the Fermi form, aiding in the evaluation of the integral.

PREREQUISITES
  • Understanding of Fermi-Dirac statistics
  • Familiarity with Bose-Einstein statistics
  • Knowledge of integral calculus
  • Experience with gamma functions and their properties
NEXT STEPS
  • Study the derivation of the Bose-Einstein integral forms
  • Learn about the properties of the gamma function in relation to statistical mechanics
  • Explore the application of Fermi-Dirac integrals in quantum statistics
  • Investigate the relationship between Fermi and Bose functions in greater detail
USEFUL FOR

Students and professionals in physics, particularly those specializing in statistical mechanics, quantum mechanics, and mathematical physics, will benefit from this discussion.

alejandrito29
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Hello, i need solve de following integral

[tex]\int ^{\infty}_0 \frac{x^3}{e^x+1} dx[/tex]

i tried with the fermi function but the factor [tex]e^x[/tex] is different to [tex]e^{x-\eta}[/tex], and with the gamma function but the factor [tex]e^x+1[/tex] is different to [tex]e^x-1[/tex].

Help please
 
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alejandrito29 said:
Hello, i need solve de following integral

[tex]\int ^{\infty}_0 \frac{x^3}{e^x+1} dx[/tex]

i tried with the fermi function but the factor [tex]e^x[/tex] is different to [tex]e^{x-\eta}[/tex], and with the gamma function but the factor [tex]e^x+1[/tex] is different to [tex]e^x-1[/tex].

Help please

The Bose and Fermi forms are related by 1/(e^x+1)-1/(e^x-1)=2/(e^(2x)-1). I know you know the Fermi form. You should be able to find the Bose form from there.
 

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