Integral of type 'derivative over function' with a twist

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SUMMARY

The integral of the function [(2x - 3) / (x^2 - 3x - 5)^2] dx can be solved using integration by substitution. By letting u = x^2 - 3x - 5, the differential du is equal to (2x - 3)dx, transforming the integral into du/u^2. This substitution simplifies the integration process, allowing for straightforward calculation of the integral.

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BalintRigo
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Homework Statement



Find the integral

[(2x - 3) / (x^2 - 3x - 5)^2] dx

Homework Equations



I noticed that if I differentiate the denominator I get the nominator, which would be a simple problem. The denominator, however is raised to the power 2.

Can I still somehow use the rule for integrals where the nominator is the derivative of the denominator? Or do I need to take a different approach?

Thank you
 
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The 'approach' you are talking about is integration by substitution, I hope. You've observed that if u=x^2-3x-5, then du=u'dx=(2x-3)dx. That's great. That turns the integral into du/u^2 in terms of u. Can you integrate that?
 
I got it, thanks an awful lot!
 

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