Integrate 4x^2+2: Solve for x=3 to x=1 - 44/3

[winston2020]

Hi, I've got to solve for: \int\stackrel{3}{1}(4x²+2)dx

This is what I've done:

= [ (4/3)x³ + 2x ]\stackrel{3}{1}
= [ (4/3)(3)³ + 2(3) ] - [ (4/3)(1)³ + 2(1) ]
then I solved...

= 44/3

Is that correct at all?

 

[sutupidmath]

looks good to me! If you have done the arithmetic correctly of course!

 

[winston2020]

looks good to me! If you have done the arithmetic correctly of course!

Awesome! My morale just sky rocketed...

By the way, sorry for the bad latex graphic thing... I'm having a hard time figuring that out.

 

[sutupidmath]

\int_{1}^3 (4x^2+2)dx

 

[winston2020]

Cool thanks. Could you check out this https://www.physicsforums.com/showthread.php?t=256875" again?

 

[truthfinder]

Your math looks good, but you made an error in your calculation. I'm getting 116/3.