Integrate (cos^2(x))/(sin^6(x))

  • Thread starter Thread starter n77ler
  • Start date Start date
  • Tags Tags
    Integrate
Click For Summary

Homework Help Overview

The problem involves integrating the function (cos^2(x))/(sin^6(x)), which falls under the subject area of calculus, specifically integration techniques.

Discussion Character

  • Exploratory, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to use double angle identities and substitution but expresses uncertainty about how to proceed with the integration. Some participants suggest a transformation to cosecant functions, while others question the reasoning behind this approach.

Discussion Status

Participants are exploring different methods of rewriting the integral, with hints provided to guide the original poster. There is a mix of understanding and confusion, with some expressing difficulty in following the suggested transformations.

Contextual Notes

The original poster indicates a lack of familiarity with similar problems, which may affect their ability to follow the discussion. There is also mention of a preference for simpler approaches, highlighting the challenge of the problem.

n77ler
Messages
89
Reaction score
0
[SOLVED] ff

Homework Statement



integrate (cos^2(x))/(sin^6(x))

Homework Equations



Double angles?
u-sub?

The Attempt at a Solution



I tried using double angles but I am really not sure what to do I havnt seen any like this... I have only done stuff without fraction like integrating cos^3x sin^5x can anyone just start me off please
 
Last edited:
Physics news on Phys.org
Hi n77ler! :smile:

Hint: it's cosec^6(x) - cosec^4(x).

Does that help … ? :smile:
 
hmm kind of I am not sure where you got that though. The division in an integral can be changed to subtration i guess... but I am not sure how you are getting the two csc's. I know it is 1/sin but not sure other than that
 
cos^2(x)/sin^6(x)

= (1 - sin^2(x))/sin^6(x) = 1/sin^6(x) - 1/sin^4(x)

= cosec^6(x) - cosec^4(x). :smile:
 
right, god lol I'm not functioning well right now.
 
ok so i separate those into two different integrals and then integrate right
 
yup :)
 
meh gave up cause it was to much parts so i went back to start and found an easier way lol...

(cos^2x/sin^2x ) (1/sin^4x) and then cot^2xcsc^4x and solved...thanks tho :)
 

Similar threads

Replies
3
Views
2K
  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 15 ·
Replies
15
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
Replies
5
Views
2K
  • · Replies 27 ·
Replies
27
Views
4K
  • · Replies 10 ·
Replies
10
Views
2K
  • · Replies 5 ·
Replies
5
Views
3K