Integrate e^2x / SQRT (e^2x + 3)

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SUMMARY

The integral of the function e2x / SQRT(e2x + 3) can be solved using substitution. By letting t = e2x + 3, the differential dt is equal to 2e2x dx, transforming the integral into (1/2) dt / SQRT(t). The correct integration leads to (1/3) SQRT(t3), which simplifies to (1/3) SQRT(e2x + 3)3. The key takeaway is the importance of correctly applying the power rule during integration.

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Homework Statement



Integrate e^2x / SQRT [(e^2x) + 3)]

Homework Equations





The Attempt at a Solution



i know the solution, is: SQRT [(e^2x) + 3]

but i have no idea why. Please I need help

thank you
 
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Have you tried substitution?
 
eok20 said:
Have you tried substitution?

yes, t=e^2x + 3 but still nothing
 
Ok, if t=e^2x + 3 then dt = 2e^2x, and what does the integral become in terms of t and dt?
 
eok20 said:
Ok, if t=e^2x + 3 then dt = 2e^2x, and what does the integral become in terms of t and dt?

i have 1/2 (dt/ sqrt t)

so 1/2 t^(3/2) / (3/2)

then sqrt t / 3

then sqrt (e^2x+3)^3 / 3

its not the solution, it may be sqrt (e^2x+3)
 
Close, you have 1/2(dt/sqrt(t)) = 1/2 t^(-1/2) dt. You integrated 1/2 t^(1/2) dt instead
 
sqrt t is in the Denominator! So the power of t isn't 1/2, but actually... ?
 
eok20 said:
Close, you have 1/2(dt/sqrt(t)) = 1/2 t^(-1/2) dt. You integrated 1/2 t^(1/2) dt instead

its true! lol, it was my mistake, i forgot the change t^1/2 -> t^-1/2

thank you!
 

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