tandoorichicken Messages 245 Reaction score 0 Thread starter Oct 13, 2004 #1 How do you integrate even powers of trig functions, such as [tex]\int\cos^{2}{\theta} \,d\theta[/tex]
How do you integrate even powers of trig functions, such as [tex]\int\cos^{2}{\theta} \,d\theta[/tex]
phy Oct 13, 2004 #2 Just an idea: perhaps you could break the integral into cos(theta)*cos(theta) and then integrate by parts from there
Just an idea: perhaps you could break the integral into cos(theta)*cos(theta) and then integrate by parts from there
relinquished™ Messages 79 Reaction score 0 Oct 14, 2004 #3 tandoorichciken, you must use an identity [tex] <br /> cos^2 \theta = \frac{1 + cos 2\theta}{2}<br /> [/tex] When the cosine function is raised to an even integer, say for example 4, [tex] cos^4 \theta = (cos^2)^2 = (\frac{1 + cos 2\theta}{2})^2[/tex] For the sine function, use the identity [tex] <br /> sin^2 \theta = \frac{1 - cos 2\theta}{2}<br /> [/tex] A word of Caution. When doing this method do not forget to double your angle ^_^
tandoorichciken, you must use an identity [tex] <br /> cos^2 \theta = \frac{1 + cos 2\theta}{2}<br /> [/tex] When the cosine function is raised to an even integer, say for example 4, [tex] cos^4 \theta = (cos^2)^2 = (\frac{1 + cos 2\theta}{2})^2[/tex] For the sine function, use the identity [tex] <br /> sin^2 \theta = \frac{1 - cos 2\theta}{2}<br /> [/tex] A word of Caution. When doing this method do not forget to double your angle ^_^