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Integrate (x^2 / sinx) / (1 + x^6):
How to do this? I just need some clues...
How to do this? I just need some clues...
Ah! That makes the problem solvable.frozen7 said:and from x = - pi / 2 to x = pi / 2
A function, f(x), is even iffrozen7 said:Erm...may I know what is odd and even function?
It IS a proper way!!frozen7 said:Ya. Thanks. Finally i catch the ball. But how should I answer this question in a proper way? Is there any other answering method for this question?
There's a little proof:frozen7 said:Ya. Thanks. Finally i catch the ball. But how should I answer this question in a proper way? Is there any other answering method for this question?
frozen7 said:By plotting the graph of sinx , the area within [tex]\frac{-\Pi}{2}[/tex] and [tex]\frac{\Pi}{2}[/tex] is zero and also know that the function is an odd function. So, what I get is only the value of sinx , how about [tex]\frac{x^2}{1+x^6}[/tex]?
Okay, you should look back at your text-book. There should be a part that states:frozen7 said:how come [tex]\int \limits_{0} ^ \alpha f(-u) du = \int \limits_{0} ^ \alpha f(u) du = \int \limits_{0} ^ \alpha f(x) dx[/tex]
Shouldn`t it be [tex]\int \limits_{0} ^ \alpha f(-u) du = \int \limits_{0} ^ \alpha f(u) du = \int \limits_{0} ^ {-\alpha} f(x) dx[/tex]