Integrating 2t^2/(1+t^2)^2 with Trig Substitution

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Homework Statement



integrate 2t^(2)/(1+t^2)^(2)

Homework Equations



trig sub 1+tan^2(x)= sec^2(x)

The Attempt at a Solution


the attempted solution is attached.
 

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Your derivation is not correct and the method you follow is a bit complicated. Try integration by parts, ∫u'vdt=uv-∫uv'dt, with u'=2t/(1+t^2)^2 and v=t.

ehild
 
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If y = (1/3)t + C, then dy/dt = 1/3, which is clearly not even remotely close to the original integrand.
 
omg! i knowwwwwwwwwwwwwwwwww! i did it. that was so stupid of me. thank you.
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
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