Integrating a Definite Integral with Trigonometric Functions

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utkarsh009
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Homework Statement


∫dt/(t^2 +2tcos a + 1)
(Limits of the integral are from 0 to 1)
(0<a<π)

Homework Equations

The Attempt at a Solution


Put t=sin a
dt=cosa da
∫dt/(t^2 +2tcos a + 1) = ∫cos a da/(sin^2 a + sin 2a + 1) [ limits of integration changed to 0 to π/2]
= ((cosec a)/2) ∫sin 2a da/(sin^2 a + sin 2a + 1)

I couldn't figure out what to do next... Please help!
 
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utkarsh009 said:

Homework Statement


∫dt/(t^2 +2tcos a + 1)
(Limits of the integral are from 0 to 1)
(0<a<π)

Homework Equations

The Attempt at a Solution


Put t=sin a
dt=cosa da
∫dt/(t^2 +2tcos a + 1) = ∫cos a da/(sin^2 a + sin 2a + 1) [ limits of integration changed to 0 to π/2]
= ((cosec a)/2) ∫sin 2a da/(sin^2 a + sin 2a + 1)
I don't know what you did in this last step, but you can't bring csc(a) out as if it were a constant.
utkarsh009 said:
I couldn't figure out what to do next... Please help!
 
Oh yes... By mistake i typed the integration symbol after it. Cosec a should be inside the integral. So, how should i proceed??
 
Oh yah... Thanks ... I solved it... But have a look at this file... I couldn't get an answer for this...
Printed multiple-choice problem: if x satisfies (integral from 0 to 1 of dt/(t^2 + 2t cos a + 1)) x^2 - (integral from -3 to 3 of t^2 sin 2t/(t^2 + 1) dt) x - 2 = 0 with 0 < a < pi, find x. Options: (A) ± sqrt(a/(2 sin a)), (B) ± sqrt(2 sin a / a), (C) ± sqrt(a/sin a), (D) ± 2 sqrt(sin a / a).