Integrating xe^{ax}: A Step-by-Step Solution

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Radarithm
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Homework Statement



Evaluate: [tex]\int{xe^{ax}}dx[/tex]

Homework Equations



Integration by substitution

The Attempt at a Solution



I'm on a phone at the moment. My work: http://postimg.org/image/v4hdr5uqx/

The correct answer was:
[tex]\frac{xe^{ax}}{a}-\frac{e^{ax}}{a^2}[/tex]
 
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http://postimg.org/image/ao3mi4ygz/

I feel like I'm getting closer but I'm still making a dumb mistake. Is it with the derivatives?
 
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If [itex]dv = e^{ax} dx[/itex], then [itex]v = e^{ax}[/itex] is wrong. There are also multiple errors on the second line, but you need to fix what I said first.
 
Got it. Thanks for pointing out my mistakes.
[tex]\int{xe^{ax}}dx[/tex] [tex]u=x du=dx dv=e^{ax}dx v=\frac{e^{ax}}{a}[/tex]
[tex]\frac{xe^{ax}}{a}-\int{\frac{e^{ax}}{a}}dx[/tex]
[tex]\frac{xe^{ax}}{a}-\int{e^{ax}a^{-1}}dx=\frac{xe^{ax}}{a}-\frac{e^{ax}}{a^2}[/tex]

Power rule + derivative mistake
Thanks for the help.