[Integration] A tough substitution problem

[gunnargolf]

Homework Statement

The following is to be evaluated using substitution or partial integration.

$$\int\frac{(2x-1)}{e^{\arctan(x)}}\,dx$$

(It's supposed to be e^(arctan(x)) but I'm new to LaTeX and can't quite figure out how I would input it correctly) (Fixed it for you.)[/color]

Homework Equations

No relevant equations

The Attempt at a Solution

I tried partial integration and that definitely does not help. I simply have no idea how I could substitute.

 

[lanedance]

how about trying integration by parts first, and let u' = 2x-1

 

[lanedance]

actually i might have to rethink that...

 

[susskind_leon]

Imho it makes sense to substitute u=arctan(x). From there, there is still some way to go though.

 

[vela]

(It's supposed to be e^(arctan(x)) but I'm new to LaTeX and can't quite figure out how I would input it correctly)

You just have to put everything in the exponent inside curly braces to group them together. Also, use a backslash before the name of common functions to get them to typeset correctly.

There's a LaTeX guide here: https://www.physicsforums.com/showthread.php?t=546968

 

[lanedance]

or noting that $\frac{d}{dx}arctan(x)= \frac{1}{1+x^2}$ you could rearrange as follows

$$\int (2x-1)e^{-arctan(x)}= 2xe^{-arctan(x)}-1e^{-arctan(x)} = 2xe^{-arctan(x)}-\frac{1+x^2}{1+x^2}e^{-arctan(x)} = 2xe^{-arctan(x)}-(1+x^2)\frac{e^{-arctan(x)} }{1+x^2}$$

which should avoid subtitution or parts all together.. though it comes from a similar idea to parts

 

[susskind_leon]

where did you carry out the integral?

 

[lanedance]

haven't done the integral, as i left that part for the OP, didn't mean to have the integral sign at the start of that expression, was rearranging to simplify the integration

 

[lanedance]

So the integral becomes

$$\int \left( 2xe^{-arctan(x)}-(1+x^2)\frac{e^{-arctan(x)} }{1+x^2} \right)dx$$

 

[sunjin09]

Homework Statement

The following is to be evaluated using substitution or partial integration.

$$\int\frac{(2x-1)}{e^{\arctan(x)}}\,dx$$

(It's supposed to be e^(arctan(x)) but I'm new to LaTeX and can't quite figure out how I would input it correctly) (Fixed it for you.)[/color]

Homework Equations

No relevant equations

The Attempt at a Solution

I tried partial integration and that definitely does not help. I simply have no idea how I could substitute.

It can be verified that (1+x^2)/e^atan(x) is the answer, hope that helps