- #1
AndrewGRQTF
- 27
- 2
This question is about the general 1 loop correction to the propagator in QFT (this is actually not important for this question). Let's say we have an integral over an integration variable x, and this x ranges from ##-\infty## to ##\infty##. If we look at this integration contour in the complex plane, it will be along the real axis. A book that I am reading (QFT by Srednicki), says that we can rotate this contour counterclockwise onto the imaginary axis, without changing the value of the integral, and he says that this is because the contour does not pass over any poles of the integrand and that the integrand vanishes fast enough as the magnitude of x goes to infinity.
My question is: why does the value of the integral not change when we change the integration contour?
My question is: why does the value of the integral not change when we change the integration contour?