Integration bessel function (simple)

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SUMMARY

The integral of the Bessel function \( J_0(ax) \) with respect to \( x \) is confirmed to be \( \int J_0(ax) x \, dx = \frac{J_1(ax) x}{a} \). To derive this result, one can substitute \( x = \frac{t}{a} \) and \( dx = \frac{dt}{a} \), which simplifies the integration process. This method effectively demonstrates the relationship between the Bessel functions \( J_0 \) and \( J_1 \) in the context of integration.

PREREQUISITES
  • Understanding of Bessel functions, specifically \( J_0 \) and \( J_1 \).
  • Knowledge of integral calculus and substitution techniques.
  • Familiarity with mathematical notation and functions.
  • Basic skills in mathematical proofs and derivations.
NEXT STEPS
  • Study the properties and applications of Bessel functions in mathematical physics.
  • Explore advanced integration techniques involving special functions.
  • Learn about the derivation of other integral identities involving Bessel functions.
  • Investigate numerical methods for evaluating Bessel function integrals.
USEFUL FOR

Mathematicians, physicists, and engineers working with Bessel functions and integral calculus, particularly those involved in mathematical modeling and analysis.

lavster
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Can someone confirm that [tex]\int J_0(ax)xdx=\frac{J_1(ax)x}{a}[/tex]? I can only find the solution if J(x) but i want J(ax) so what i did above makes logical sense to me but i can't find it anywhere. thanks
 
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That's alright.
Just let x=t/a and dx=dt/a in order to prove it.
 
excellent - thanks!
 

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