- #1

clope023

- 992

- 131

**[SOLVED] integration by partial fractions**

## Homework Statement

[tex]\int[/tex]((2x^2-1)/(4x-1)(x^2+1))dx

## Homework Equations

A1/ax+b + A2/(ax+b)^2 + ... + An/(ax+b)^n

## The Attempt at a Solution

(2x^2-1)/(4x-1)(x^2+1) = A/4x-1 + Bx+C/x^2+1

2x^2-1/x^2+1 = A + Bx+C(4x-1)/x^2+1

set x = 1/4, get

-14/17 = A + B(0), A = -14/17

I'm pretty much stuck here; I just need to get the values for B and C and I can solve it from there, any help is greatly appreciated.