1. The problem statement, all variables and given/known data (2x^3-2x+1)/(x^2/3x) Find the integral. 2. The attempt at a solution So I've been on this problem for like an hour now and I don't know what I'm doing wrong. So I used long division and got 2x+ (4x+1)/(x^2-3x) ∫2x + ∫(4x+1)/(x^2-3x) = x^2 + ∫(4x+1)/(x^2-3x). For that next part, I used partial fractions. A/x + B/(x-3) = 4x+1 Solved for a= -1/3 Solved for b= 13/3 Put everything together and solving for that integral, I got x^2- 1/3ln(x) + 13/3ln(x-3) and it's wrong. Where am I going wrong? I'm so confused. Thank for any help in advance.