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## Homework Statement

(2x^3-2x+1)/(x^2/3x)

Find the integral.

**2. The attempt at a solution**

So I've been on this problem for like an hour now and I don't know what I'm doing wrong. So I used long division and got

2x+ (4x+1)/(x^2-3x)

∫2x + ∫(4x+1)/(x^2-3x)

= x^2 + ∫(4x+1)/(x^2-3x).

For that next part, I used partial fractions.

A/x + B/(x-3) = 4x+1

Solved for a= -1/3

Solved for b= 13/3

Put everything together and solving for that integral, I got

x^2- 1/3ln(x) + 13/3ln(x-3)

and it's wrong.

Where am I going wrong? I'm so confused.

Thank for any help in advance.