- #1

sreerajt

- 39

- 1

(V-M)(dP/dx)+3P(dV/dx)=0, (where M,P and V are constants).

If you integrate with dx, you will get:

∫[(V-M)dP]+∫[3PdV]=0.

which ultimately results in the answer M=4V.

Now, i can put the first equation in this form also:

(dP/P)=-3[dV/(V-M)]. Integration will give you,

lnP=-3ln(V-M) , where 'ln' is the logarithm to base e. This give lnP+ln[(V-M)

^{3}]=0.

This gives entirely different answer. So which is the correct way??

Thanks in advance...